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Order ArrayList with Int and String in Kotlin Android ?

Yogesh Kumar
04-May-2022
0

the problem is that you have "Jack" two times in it. things.set(things.indexOf("Jack"), 11); only changes the first one to 11, not the second one.

 val things = arrayOf<Any>("Jack", 8, 2, 6, "King", 5, 3, "Queen", "Jack");
things.set(things.indexOf("Jack"), 11);
things.set(things.indexOf("Queen"), 12);
things.set(things.indexOf("King"), 13);
println(things.contentToString()) //prints [11, 8, 2, 6, 13, 5, 3, 12, Jack]

Now, how I maybe would do it, is like this:

 fun main() {
    val things = arrayOf("Jack", 8, 2, 6, "King", 5, 3, "Queen", "Jack")
    things.sortWith(compareBy { it.toInt() })
    println(things.contentToString()) //prints [2, 3, 5, 6, 8, Jack, Jack, Queen, King]
}

val mapping = mapOf("Jack" to 11, "Queen" to 12, "King" to 13)

fun Any.toInt() : Int {
    if (this is Int) return this
    return mapping[this] ?: 0
}